請問下列問題該如何解答?
Express 0.64 64 64 64......(A Repeating/ Terminating decimal) as an infinite geometric series.
Thanks :)
Infinite Geometric Series
2013-03-27 9:00 am
回答 (3)
2013-03-27 9:46 am
✔ 最佳答案
0.64 64 64 64......= 0.64 + 0.64x0.01 + 0.64x0.01² + 0.64x0.01³ + ...... to ∞ term
*****
To calculate the answer :
It is infinite geometric series with a1 = 0.64 and r = 0.01
S∞ = a1/(1 - r)
Hence, 0.64 64 64 64......
= 0.64(1 - 0.01)
= 0.64/0.99
= 64/99
(The question itself does not require to calculate the answer.)
參考: 胡雪
2013-03-29 10:29 am
請知識長看清楚題目，不是要計算答案，而是：
Express as an infinite geometric series.
Express as an infinite geometric series.
2013-03-27 9:50 pm
Sol
A= 0.64 64 64 64......
100A=64.646464……
99A=100A－A=64
A=64/99
A= 0.64 64 64 64......
100A=64.646464……
99A=100A－A=64
A=64/99
收錄日期: 2021-04-13 19:23:39
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130327000051KK00023