F.3 chem 平衡方程式

2013-03-15 4:11 am

平衡以下方程式:
H3PO4 + (NH4)2MoO4 + HNO3 → (NH4)3PO4·MoO3 + NH4NO3 + H2O
HCl + KMnO3 → MnCl2 + H2O + Cl2 + KCl
Cu + HNO3 → NO2 + H2O + Cu(NO3)2
(以上所有數字為下標)

Balance to below procedure:
H3PO4 + (NH4)2MoO4 + HNO3 → (NH4)3PO4· MoO3 + NH4NO3 + H2O
HCl + KMnO3 → MnCl2 + H2O + Cl2 + KCl
Cu + HNO3 → NO2 + H2O + Cu(NO3)2
(All of the above numbers as subscripts)

回答 (2)

Ka ho

2013-03-20 4:13 am

✔ 最佳答案

H3PO4 + 12 (NH4)2 MoO4 + 21 HNO3
--> (NH4)3(PO4)．12 MoO3 + 21 NH4NO3 + 12 H2O
---------------------------------------------------------------------------------
16HCl + 2KMnO4 --> 2MnCl2 + 8H2O + 5Cl2 + 2KCl
---------------------------------------------------------------------------------
Cu + 4HNO3 --> 2NO2 + 2H2O + Cu(NO3)2
---------------------------------------------------------------------------------

👍 0 👎 0

superjerry

2013-03-16 4:56 am

2H3PO4 + 2(NH4)2MoO4 + 3HNO3 → 2(NH4)3PO4· MoO3 + 3NH4NO3 +
5H2O
6HCl + KMnO3 → MnCl2 + 3H2O + Cl2 + 2KCl
5Cu + 12HNO3 → NO2 + 6H2O + 5Cu(NO3)2

👍 0 👎 0

收錄日期: 2021-04-13 19:22:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130314000051KK00310

檢視 Wayback Machine 備份