(x+1)/|x-1| >0
請寫埋STEPS加解釋 THX
Absolute Value, 點樣分CASES計呀?
2013-03-14 11:23 pm
回答 (2)
2013-03-15 9:48 am
✔ 最佳答案
螞蟻雄兵的方法最快.
大概你要的是分 case.
(x+1)/| x-1 | >0
考慮
情況(1): x<1(x+1)/| x-1 | >0(x+1)/[-(x-1)]>0(x+1)/(x-1)<0(x+1)(x-1)<0so -1 < x < 1.
情況(2): x>1(x+1)/| x-1 | >0(x+1)/(x-1)>0(x+1)(x-1)>0so x < -1 or x > 1.in this case, x > 1.
Combining the 2 cases: -1 < x < 1 and x > 1.
參考: Additional Mathematics
2013-03-15 12:17 am
(x+1)/｜x－1｜>0
Sol
(x+1)/｜x－1｜>0
(x+1)｜x－1｜>0
x+1>0，x<>1
x>－１，x<>1
Sol
(x+1)/｜x－1｜>0
(x+1)｜x－1｜>0
x+1>0，x<>1
x>－１，x<>1
收錄日期: 2021-04-13 19:22:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130314000051KK00159