所以想問一題的解法,請詳解謝謝
(a)x^2+6xy-16y^2=(x+8y)(x-2y)
(b)x^2+6xy-16y^2-2xz-16yz
更新1:
請問(a)是如何解出這答案的?
數學-因式分解一問
2013-03-12 10:19 pm
正在溫數,但因式分解這部分很差
所以想問一題的解法,請詳解謝謝
(a)x^2+6xy-16y^2=(x+8y)(x-2y)
(b)x^2+6xy-16y^2-2xz-16yz
所以想問一題的解法,請詳解謝謝
(a)x^2+6xy-16y^2=(x+8y)(x-2y)
(b)x^2+6xy-16y^2-2xz-16yz
回答 (1)
2013-03-12 11:34 pm
✔ 最佳答案
答案：(x + 8y)(x - 2y - 2z)x^2 + 6xy - 16y^2 - 2xz - 16yz
= (x + 8y)(x - 2y) - 2xz - 16yz (利用 a 的結果)
= (x + 8y)(x - 2y) - 2z(x + 8y)
= (x + 8y)[(x - 2y) - 2z]
= (x + 8y)(x - 2y - 2z)
參考: knowledge
收錄日期: 2021-04-28 14:41:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130312000051KK00113