Help and explain? What's (3 - 4i) (-2 + 6i)?

(3 - 4i)(-2 + 6i)
= -6 + 8i + 18i - 24i^2
= -6 + 26i + 24
= 18 + 26i
= 2(9 + 13i)

(3 - 4i)(-2 + 6i) = -6 + 18i + 8i - 24(i^2)

= -6 + 24 + 26i

= 18 + 26i

(3 - 4i)(- 2 + 6i)
= - 6 + 18i + 8i - 24i^2
= - 6 + 24 + 26i
= 18 + 26i
= 2(9 + 13i) Ans.

FOIL it

Let's try it with x instead of i

(3 - 4x) (-2 + 6x) = -24x^2 + 26x - 6

so
(3 - 4i) (-2 + 6i) = -24i^2 + 26i - 6

But i^2 = -1

So we can simplify further

-24(-1) + 26i - 6 = 18 + 26i

(3-4i)(-2+6i)

Use FOIL First outside inner last

3*-2 =-6
3*6i = 18i
-2*-4i = 8i
-4i*6i = 24i^2

= -6 + 18i - 8i - 24i^2

= 2 (-3 + 5i -2i^2)
Factored

Simplify

= -6 +10i - 24i^2

(3-4i)(2-6i)
-------------
Multiply like any 2 binomials.
(3-4i)(2-6i)

= 3(2-6i) - 4i(2-6i)
= 6-18i+-8i+24^2
= 6 - 26i +24*(-1)
= -18 - 26i