In a hand of 13 cards drawn randomly from a pack of 52, find the chance of at least one ace but no other court cards.
答案系 (40C13) / (52C13) - (36C13) / (52C13)
我吾明可吾可以解釋一下
Random sampling
2013-03-10 9:54 pm
回答 (1)
2013-03-13 5:57 am
✔ 最佳答案
coutr cards 指 J Q K﹐共有12隻題目問至少有1隻A及不會有 J Q K的13張組合數目
等於N(沒有 J Q K的13張組合數目) - N(沒有A J Q K的13張組合數目)
= (40C13)/(52C13) - (36C13)/(52C13)
收錄日期: 2021-04-27 17:44:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130310000051KK00152