請解答下列網址的第一題(Q1)：
https://docs.google.com/document/d/1GYPN1AVRrmbpyrRdRaTtqvBumCQ-RDEbGCIFH0Qn5SQ/edit?usp=sharing
數學題目(續三角)一問
2013-03-05 8:14 am
回答 (1)
2013-03-05 9:33 am
✔ 最佳答案
Some special angles :sin0° = 0, sin90° = 1, sin180° = 0, sin270° = -1
cos0° = 1, cos90° = 0, cos180° = -1, cos270° = 0
[sin²90° + cos²90°] / [3sin³270° - cos180°]
= [(0)² + (1)²] / [3 x (-1)² - (-1)]
= [0 + 1] / [-3 + 1]
= -1/2
參考: micatkie
收錄日期: 2021-04-13 19:20:02
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130305000051KK00016