Probability pdf Expected Value

2013-02-25 12:08 am
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更新1:

Can you also answer the following two questions? I just need to check if my answers are correct. 1. The joint probability density function of X and Y is given by f(x,y)= C(y-x) e^(-y) where -y

更新2:

請看我的意見

更新3:

-y

更新4:

i ve posted another question named "Probability pdf questions"

更新5:

please answer that also thanks!!!

更新6:

also for your solution in #3, the expected value will be equals to 0 , because of the negative sign, how come it will become 2/(a+1)(a+2) ?????

更新7:

ohhhh i get it thanks!

更新8:

自由自在 ( 知識長 ): In question #2, why is P(X1 > x/n) , P(X2 > x/n), ..........= (1 - x/n) ??????

回答 (2)

2013-02-25 2:19 am
✔ 最佳答案
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2013-02-26 20:12:24 補充:
X1,X2,... are random number in (0,1). This mean X1, X2,... follow uniform distribution with pdf = 1.
2013-02-25 3:23 am
Can you also answer the following two questions? I just need to check if my answers are correct.

1. The joint probability density function of X and Y is given by f(x,y)= C(y-x) e^(-y) where -y



2013-02-24 19:25:00 補充:
where -y




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