oxygen gas generated by the decomposition of potassium chlorate is collected over water. the volume of gases collected at 24℃ and 101.6 kPa is 0.128 dm^3. calculate the mass (in grams) of oxygen gas obtained. the pressure of the water vapour at 24℃ is 2.99 kPa
(Given: R=8.314 kPa dm^3 mol^-1 K^-1)
physical chem 問題
2013-02-19 5:31 am
回答 (1)
2013-02-19 6:00 am
✔ 最佳答案
Pressure, P = 101.6 - 2.99 = 98.61 kPaVolume, V = 0.128 dm³
Absolute temperature, T = 273 + 24 = 297 K
Molar mass, M = 16 x 2 = 32 g mol⁻¹
Gas constant, R = 8.314 kPa dm³ mol⁻¹ K⁻¹
PV = nRT
PV = (m/M)RT
m = MPV/(RT)
Mass of O2, m = 32 x 98.61 x 0.128 / (8.314 x 297) = 0.164 g
參考: 賣女孩的火柴
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