1. [9^n/2)·2^2n·3^n]/2^n
=
F4 maths
2013-02-17 7:43 pm
回答 (1)
2013-02-17 8:55 pm
✔ 最佳答案
[9^(n/2) * 2^2n * 3^n] / 2^n=(3^n * 4^n * 3^n) / 2^n
=(3*4*3/2)^n
=18^n //
收錄日期: 2021-04-13 19:18:00
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130217000051KK00117