✔ 最佳答案
1
Set y^3=7+x
y=(7+x)^(1/3)
x-2=9-y^3
y+(9-y^3)^(1/3)=3
(9-y^3)^(1/3)=3-y
9-y^3=27-27y+9y^2-y^3
9y^2-27y+18=0
y^2-3y+2=0
(y-1)(y-2)=0
y=1 or y=2
(1) y=1
x=y^3-7=-6
(2) y=2
x=y^3-7=1
2.
Set y=√(x+2)
y^2=x+2
x=y^2-2
x^2+x+6√(x+2)=18
(y^4-4y^2+4)+(y^2-2)+6y=18
y^4-3y^2+6y-16=0
(y^2+3y+4)(y^2-4)=0
y^2+3y+4<>0
y^2-4=0
y=2 or y=-2(reject)