數學最大的數

2013-02-09 9:27 am
題目:用3個9所能寫出最大的數是多少?

我真的想不出來幫忙謝謝

回答 (3)

2013-02-09 10:26 am
✔ 最佳答案
9^(9^9)=9^387420489=9的387420489次方

即 9×9×9×9×9×9×9.............×9

總共有 387420489個9相乘,將近有4億個9相乘。


2013-02-09 02:33:24 補充:
取 log 9(9^9) = 387420489×(log 9)
= 387420489×0.9542 = 369676630.6

所以這個數有 369676631 位,將近3億7000萬位

2013-02-09 15:28:01 補充:
Tetration uses 2"9"s only,not 3"9"s
....9.....
......9...
3"9"s (or more) is no more called teration,it's called pentation.
In the case of 9"9"s used,It's written as
"9↑↑↑9" or "9↑3 9"

2013-02-09 15:31:06 補充:
Still, only 2"9"s used,not 3"9"s.

In the case of 3"9"s used,It's written as
"9↑↑↑3" or "9↑3 3"
Only one "9" used.
That's why I didn't use teration or pentation or the answers.

2013-02-09 15:31:47 補充:
I'm not sure if repeated tetration can be used or not,
If this is the case,then I agree the number can be bigger.
....9..........
......9........
........9......

2013-02-09 15:33:31 補充:
correction:

That's why I didn't use teration or pentation for the answers.
2013-02-09 10:52 pm
For example tetration, pentation, ...
2013-02-09 8:32 pm
應該寫出所能使用之(二元)運算,否則要多大都可以。


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