Maths(Laws of integral indices
回答 (3)
2013-02-10 5:04 pm
✔ 最佳答案
[(2*5^n)^2+25^n]/5^n=(2^2*5^(2n)+5^2n)/5^n=4*5^n+5^n=(4+1)*5^n=5*5^n=5^(n+1)........ans
2013-02-18 5:10 am
[(2*5^n)^2+25^n]/5^n
=(2^2*5^(2n)+5^2n)/5^n
=4*5^n+5^n
=(4+1)*5^n
=5*5^n
=5^(n+1)........ans
=(2^2*5^(2n)+5^2n)/5^n
=4*5^n+5^n
=(4+1)*5^n
=5*5^n
=5^(n+1)........ans
2013-02-17 10:04 pm
Hi I am marcoleongk89,today I am going to help you solve the question.
[(2*5^n)^2+25^n]/5^n
=[2^2*5^2n + 25^n]/5^n
=(4*5^2n+5^2n)/5^n
=(5*5^2n)/5^n<Because 4 * a + a = 5 * a ! You just think 5^2n = a is ok.
=5^1+2n-n
=5^1+n
I ask my teacher about this question too!And she taught me this method !
Hope I can help you la ....
[(2*5^n)^2+25^n]/5^n
=[2^2*5^2n + 25^n]/5^n
=(4*5^2n+5^2n)/5^n
=(5*5^2n)/5^n<Because 4 * a + a = 5 * a ! You just think 5^2n = a is ok.
=5^1+2n-n
=5^1+n
I ask my teacher about this question too!And she taught me this method !
Hope I can help you la ....
參考: You can turn your book to page 9.4 - 9.10.There are many examples
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