硫酸銅晶體CaSO4.XH2O含結晶水36.0%

2013-02-05 4:54 am

硫酸銅晶體CaSO4.XH2O含結晶水36.0% 今取此物5克加熱至100度C得CuSO4.YH2O 3.56克又將CuSO4.YH2O加熱至250度C得CuSO4.ZH2O 3.20克則

1.X=

2.Y=

3.Z=

4.方程式係數和為何

更新1:

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更新2:

http://tw.knowledge.yahoo.com/question/question?qid=1613012602915 http://hk.knowledge.yahoo.com/question/question?qid=7013020100070 http://hk.knowledge.yahoo.com/question/question?qid=7013020200161 這幾題的題目有人之到答案嗎

更新3:

答案是 1.X = 5 2.Y =1 3.Z = 0 4.2CuSO4•5H2O(s) → 2CuSO4•(1/2)H2O(s) + 9H2O(l) 係數和為 13 2CuSO4•(1/2)H2O(s) →2CuSO4(s) + H2O(l) 係數和為 5

回答 (1)

wanszeto

2013-02-05 7:51 am

✔ 最佳答案

1.
CuSO4 的式量 = 64 + 32 + 16*4 = 160
H2O 的式量 = 1x2 + 16 = 18

CuSO4•XH2O 中，莫耳數比CuSO4 : H2O
= (100-36)/160 : 36/18
= 0.4 : 2
= 1 : 5

X = 5

2.
5 g CuSO4•XH2O 含 CuSO4質量 = 5 x (1 - 36%) = 3.2 g
5 g CuSO4•XH2O 含 H2O質量 = 5 x 36% = 1.8 g

3.56 g CuSO4•YH2O 含CuSO4 質量 = 3.2 g
3.56 g CuSO4•YH2O 含 H2O質量 = 3.56 - 3.2 = 0.36 g

CuSO4•XH2O 中，莫耳數比CuSO4 : H2O
= 3.2/160 : 0.36/18
= 0.4 : 0.2
= 1 : 1/2

Y = 1/2

3.
3.2 g CuSO4•ZH2O 含CuSO4 質量 = 3.2 g
3.2 g CuSO4•ZH2O 含 H2O質量 = 3.2 - 3.2 = 0 g

Z = 0

4.
2CuSO4•5H2O(s) → 2CuSO4•(1/2)H2O(s) + 9H2O(l)
係數和 = 2 + 2 + 9 = 13

2CuSO4•(1/2)H2O(s) →2CuSO4(s) + H2O(l)
係數和 = 2 + 2 + 1 = 5

參考: wanszeto

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