1.16d*8次方 / (2D*2次方)*2次方
2.[(2C)*3次方 * (3C*3次方)*2次方 ] / (4C)*4次方
This 2 question is from mathematics in action 2b Page 9.11 Further practice
(3 and 4)
收錄日期: 2021-04-16 15:32:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130203000051KK00276