a) 2
b) 0
c) 4
d) 1
and how
if (x-1)^4=16,then the sum of non real complex values of x=?
2013-01-29 10:57 am
回答 (2)
2013-01-29 11:06 am
✔ 最佳答案
(x - 1)^4 = 16(x - 1)^4 - 2^4 = 0
[(x - 1)^2 + 2^2][(x - 1)^2 - 2^2] = 0
[(x - 1) + 2i][(x - 1) - 2i][(x - 1) + 2][(x - 1) - 2] = 0
x = 1 - 2i, 1 + 2i, -1 or 3
Therefore, the sum of non real complex values of x
= 1 - 2i + 1 + 2i
= 2 (option a)
2013-01-29 7:07 pm
(x-1)^4=16
x-1 = 4^V16
x-1 = 2
x = 2+1
x=3
x-1 = 4^V16
x-1 = 2
x = 2+1
x=3
收錄日期: 2021-05-01 14:45:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130129025701AA7Xzkb