數學SIN COS一問.........

2013-01-30 4:15 am
(cos 0)^2+(cos 2)^2+ (cos 4)^2+...+(cos 180)^2=?

回答 (1)

2013-01-31 4:55 am
✔ 最佳答案
cos(180 - x) = -sin x

因此 (cos 0)^2 + (cos 2)^2 + (cos 4)^2 +...+ (cos 180)^2

= (cos 0)^2 + (cos 2)^2 + (cos 4)^2 +...+ (cos 90)^2
(sin 0)^2 + (sin 2)^2 + ... + (sin 88)^2

= 1 + 1 + ... + 1 + 1

= 45



收錄日期: 2021-04-27 17:43:29
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