✔ 最佳答案
1. Bu Hooke's law, k(xo) = mg where k is the spring constant
k = mg/(xo)
2. When the mass performs SHM(簡諧運動)
Period T = 2.pi.[square-root(m/k)] = 2.pi.square-root[m.(xo)/mg] = 2.pi.square-root[(xo/g)]
3. Since amplitude of oscillation = (xo/2)
distance below point of natural length = (xo - xo/2) = xo/2
4. The max spring force is experienced at point B,
Force = k.(Xo+xo/2) = 3k(xo)/2 = 3(mg/xo).(xo)/2 = 3mg/2
5. Max acceleration occurs at B.
Angular fequency w = square-root[k/m] = square-root[(mg/xo)/m] = square-root[g/xo]
Max acceleration = w^2.A where A is the amplitude of oscillation
Max acceleration = (g/xo).(xo/2) = g/2
