✔ 最佳答案
Let P(x, y) be the projection of (4, 5) on L
since L is perpendicular to the line joined P and (4,5),
[(y - 1)/(x - 1)] [(y - 5)/(x - 4)] = -1
(y - 1)(y - 5) = -(x - 1)(x - 4)
x² + y² - 5x - 6y + 9 = 0 ---------------------------------------------- (i)
since the distance from P to (4, 5) = 2
√[(x - 4)² + (y - 5)²] = 2
(x - 4)² + (y - 5)² = 4
x² + y² - 8x - 10y + 37 = 0 ----------------------------------------- (ii)
(i) - (ii), 3x + 4y - 28 = 0 => x = (28 - 4y)/3
substitute x = (28 - 4y)/3 into (i),
[(28 - 4y)/3]² + y² - 5[(28 - 4y)/3] - 6y + 9 = 0
(28 - 4y)² + 9y² - 15(28 - 4y) - 54y + 81 = 0
16y² - 224y + 784 + 9y² - 420 + 60y - 54y + 81 = 0
25y² - 218y + 445 = 0
y = (218 ± √3024) / 50 = (109 ± 6√21) / 25
I think you should know how to do next!!!