✔ 最佳答案
Equivalent resistance of the circuit = 1 + (4)(5)/(4 + 5) = 1 + 20/9 = 29/9 kohms.
(i) Ir1 = Is = 15/(29/9) = 135/29 mA.
(ii)Vr1 = Ir1 x R1 = 135/29 x 1 = 135/29 V.
(iii) Vr2 = E - Vr1 = 15 - 135/29 = 300/29 V.
(iv) Ir3 = Vr2/R3 = (300/29)/5 = 60/29 mA.
(v) Ir2 = Ir1 - Ir3 = 135/29 - 60/29 = 75/29 mA.