In the blow question, make the letter in the square brackets the subject of the formula.
( 1 ) A = 2πr(r + h) [h]
我的計法 : A = 2πr(r + h)
A - 2πr = r + h
(A - 2πr)/r = h
h = (A - 2πr)/r
但答案是 h = A / 2πr - r ,
我那裹不對 ??
thanks
Form 2 Maths :Formulas
2013-01-20 12:31 am
回答 (3)
2013-01-23 8:23 am
✔ 最佳答案
First step should be :A = 2πr(r + h)
A=2πr(r) +2πr( h)
Then u will get a correct answer.
2013-01-21 6:37 pm
第一步以經錯左
我的做法:
A = 2πr(r + h)
A/(2πr)=r+h
h=A/(2πr) -r
我的做法:
A = 2πr(r + h)
A/(2πr)=r+h
h=A/(2πr) -r
2013-01-20 12:39 am
A= 2πr(r+h)
A/2πr = r+h
h=A/2πr - r
--------------------
乘變除 加變減
你乘變減 加變除當然錯了...
A/2πr = r+h
h=A/2πr - r
--------------------
乘變除 加變減
你乘變減 加變除當然錯了...
收錄日期: 2021-04-13 19:15:48
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20130119000051KK00211