F.4 Maths

2013-01-09 7:33 am

解8^2x+1+4^3x-1=33

回答 (3)

2013-01-09 7:39 am

✔ 最佳答案

8^(2x + 1) + 4^(3x - 1) = 33

2^(6x + 3) + 2^(6x - 2) = 33

2^(6x - 2)(32 + 1) = 33

2^(6x - 2) = 1

6x - 2 = 0

x = 1/3

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2013-01-14 3:49 am

8^(2x + 1) + 4^(3x - 1) = 33

2^(6x + 3) + 2^(6x - 2) = 33

2^(6x - 2)(32 + 1) = 33

2^(6x - 2) = 1

6x - 2 = 0

x = 1/3

參考: :)))))

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2013-01-09 7:48 am

8^(2x + 1) + 4^(3x - 1) = 33

2^(6x + 3) + 2^(6x - 2) = 33

2^(6x - 2)(32 + 1) = 33

2^(6x - 2) = 1

6x - 2 = 0

x = 1/3

參考: ^^

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