F.4 Maths

2013-01-09 7:33 am
解8^2x+1+4^3x-1=33

回答 (3)

2013-01-09 7:39 am
✔ 最佳答案
8^(2x + 1) + 4^(3x - 1) = 33

2^(6x + 3) + 2^(6x - 2) = 33

2^(6x - 2)(32 + 1) = 33

2^(6x - 2) = 1

6x - 2 = 0

x = 1/3
2013-01-14 3:49 am
8^(2x + 1) + 4^(3x - 1) = 33

2^(6x + 3) + 2^(6x - 2) = 33

2^(6x - 2)(32 + 1) = 33

2^(6x - 2) = 1

6x - 2 = 0

x = 1/3
參考: :)))))
2013-01-09 7:48 am
8^(2x + 1) + 4^(3x - 1) = 33

2^(6x + 3) + 2^(6x - 2) = 33

2^(6x - 2)(32 + 1) = 33

2^(6x - 2) = 1

6x - 2 = 0

x = 1/3
參考: ^^


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