某化學工廠之廢水為Hg2+的重量百分率為0.0003%

2013-01-06 8:41 pm
某化學工廠之廢水為Hg2+的重量百分率為0.0003% 此廢水之Hg2+含量應為多少ppm

回答 (2)

2013-01-06 9:04 pm
✔ 最佳答案
1 ppm = 1 x 10⁻⁶

此廢水之Hg²⁺含量
= 0.0003%
= 0.0003% x (1 x 10⁶) x (1 x 10⁻⁶)
= 3 x 10⁻⁶
= 3 ppm


若不用科學記數法:
1 ppm = 1/1000000

此廢水之Hg²⁺含量
= 0.0003%
= 0.0003% x (1000000/1000000)
= 3/1000000
= 3 ppm
參考: Adam
2013-01-08 1:55 am
可以去請教化學老師~~~


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