S.5 數學 points of intersection.

2013-01-04 2:27 am
Do the circle (x+a)^2 + (y-b)^2 = a^2 + sb^2 (where a>0, b>0)
and the intersect at two distinct points?

立果2條式
一條係樓上果條
仲有一條係乜? 詳細列明點解

THANKS ^^ !!!!!

回答 (2)

2013-01-04 5:25 am
✔ 最佳答案
當然係
(y-b)/(x+a)=T
T係REAL MUNBER
任何直徑的延線都intersect circle at two distinct points

2013-01-03 21:26:31 補充:
NUMBER...
參考: 還是說另一條都是要圓方程? ... 自己
2013-01-10 3:27 am
can you mention the question more precisely?


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