294克CaCl2 2H2O溶於528克水中

1.
溶質（CaCl2•2H2O）= 294 g


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2.
溶液體積
= 溶液質量 / 溶液密度
= (294 + 528) / 1.2
= 685 mL


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3.
CaCl2•2H2­O的莫耳質量 = 40 + 35.5x2 + 2x(1x2 +16) = 147 g/mol
CaCl2•2H2­O的莫耳數 = 294/147 = 2 mol
溶液體積 = 685 mL = 0.685 L
體積莫耳濃度 = 2/0.685 = 2.92 M


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4.
CaCl2•2H2­O的莫耳數 = 294/147 = 2 mol
溶劑（水）重量 = 528 g = 0.528 kg
體積莫耳濃度 = 2/0.528 = 3.79 m


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5.
重量百分率 = [294/(294 + 528)] x 100%= 35.8%