MQ63 --- ReducibilityDifficulty: 40% Prove that (21n + 4)/(14n + 3) is irreducible for all n ∈ ℕ.
MQ63 --- Reducibility
2012-12-30 7:13 pm
回答 (1)
2012-12-30 7:56 pm
✔ 最佳答案
By Euclidean algorithm(21n + 4, 14n + 3)
= (14n + 3, 7n + 1)
= (7n + 1, 1)
= 1
The G.C.D. of 21n + 4 and 14n + 3 is 1 and thus (21n + 4)/(14n + 3) is irreducible
收錄日期: 2021-04-13 19:12:42
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