化肥的奧數題
回答 (1)
2012-12-30 8:14 pm
✔ 最佳答案
設甲倉原有化肥x袋﹐則乙倉原有300 - x袋依題意
(2/3)(x - 30) - 50 = 300 - x + 30
(2/3)(x - 30) - 50 = 330 - x
(2/3)(x - 30) = 380 - x
2x - 60 = 1140 - 3x
5x = 1200
x = 240
因此甲倉原有化肥240袋﹐則乙倉原有60袋
收錄日期: 2021-04-27 17:45:03
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121230000051KK00059