1.
lim(x→0) (√(1+x^2)-1)/x
2.
lim(x→∞) (√(x)-√(x+1))
limit
2012-12-29 6:10 am
回答 (1)
2012-12-29 7:30 am
✔ 最佳答案
1. lim(x→0)_(√(1+x^2)－1)/x=lim(x→0)_(√(1+x^2)－1)(√(1+x^2)+1)/｛x[√(1+x^2)+1]｝
=lim(x→0)_[(1+x^2)－1)]/｛x[√(1+x^2)+1]｝
=lim(x→0)_x/[√(1+x^2)+1]｝
=0
2.lim(x→∞)_[√x－√(x+1)]
=lim(x→∞)_｛[√x－√(x+1)]*[√x+√(x+1)]/[√x+√(x+1)]｝
=lim(x→∞)_｛[x－(x+1)]/[√x+√(x+1)]｝
=－lim(x→∞)_｛1/[√x+√(x+1)]｝
=0
收錄日期: 2021-04-13 19:12:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121228000051KK00438