f.3 circular cones

4(a) Volume = (1/3)πr^2 h = 144π(1/3)πr^2(r/4) = 144πr = 12(b) slant = √(12^2 + 3^2) = 12.3693169Total surface area= πrl + πr^2= π(12)(12.3693169) + π(12)^2= 918.702 cm^25(a) We have πrl = 260π26πr = 260πr = 10Base area = πr^2 = 100π cm^2(b) height = √(26^2 - 10^2) = 24Volume = (1/3)πr^2 h = (1/3)π(10)^2(24) = 800π cm^3