(1)a new car is worth $250 000 and its depreciation rate is 30% for the first year and 20% for every subsequent year
(a) find its value 3 years later
(b) find the overall percentage change in its value over these 3 years
(2) jack deposits $80 000 in a bank at 6% p.a. for 2 year. find the mount obtained if the interest is compounded
(a) quarterly
(b) monthly
S3 math!!!
2012-12-27 1:32 am
回答 (2)
2012-12-27 2:14 am
✔ 最佳答案
(1)(a)
The value of the car 3 years later
= $250 000 x (1 - 30%) x (1 - 20%)²
= $112 000
(b)
Overall percentage change
= [(112 000 - 250 000)/250 000] x 100%
= -55.2%
(decrease 55.2%)
=====
(2)
(a)
Principal, P = $80 000
Interest rate, R% = 6%/4 = 1.5%
No. of periods, n = 2 x 4 = 8
Amount, A
= P (1 + R%)^n
= $80 000 x (1 + 1.5%)^8
= $90 119.41 (to 2 decimal places)
(b)
Principal, P = $80 000
Interest rate, R% = 6%/12 = 0.5%
No. of periods, n = 2 x 12 = 24
Amount, A
= P (1 + R%)^n
= $80 000 x (1 + 0.5%)^24
= $90 172.78 (to 2 decimal places)
2012-12-26 22:48:44 補充：
(2)(a)
Amount, A = $90 119 (to the nearest dollar)
(2)(b)
Amount, A = $90 173 (to the nearest dollar)
2012-12-26 22:55:40 補充：
(2)
If it is 1 year instead of 2 years, the solutions are :
(a)
Principal, P = $80 000
Interest rate, R% = 6%/4 = 1.5%
No. of periods, n = 4
Amount, A
= P (1 + R%)^n
= $80 000 x (1 + 1.5%)^4
= $84 909 (to the nearest dollar) ...... ans
2012-12-26 22:55:52 補充：
(b)
Principal, P = $80 000
Interest rate, R% = 6%/12 = 0.5%
No. of periods, n = 12
Amount, A
= P (1 + R%)^n
= $80 000 x (1 + 0.5%)^12
= $84 934 (to the nearest dollar) ...... ans
參考: Adam, Adam, Adam
2012-12-30 2:23 am
1a)
Its value
=250,000(1-30%)(1-20%)^2
=$112,000
1b)
The change
=(112,000-250,000)/250,000 x 100%
= -55.2%
Thus, the value decreased by 55.2%
2a)
Amount
=80,000[1+(6%/4)]^4
=$84,909, corr to the nearest $1
2b)
Amount
=80,000[1+(6%/12)]^12
=$84,934, corr. to the nearest $1
Its value
=250,000(1-30%)(1-20%)^2
=$112,000
1b)
The change
=(112,000-250,000)/250,000 x 100%
= -55.2%
Thus, the value decreased by 55.2%
2a)
Amount
=80,000[1+(6%/4)]^4
=$84,909, corr to the nearest $1
2b)
Amount
=80,000[1+(6%/12)]^12
=$84,934, corr. to the nearest $1
收錄日期: 2021-04-16 15:24:57
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