不會算十字交乘法

解下列各一元二次方程式:
12分之1(x-3)^2=3分之1x
==>(x-3)^2/12 -(4x/12)=0
==>[(x-3)^2-4x]/12=0
==>x^2-10x+9=0
==>(x-9)(x-1)=0
==>x=9,x=1




(x+2)^2=(2x-1)(x+2)
[請使用因式分解法解一元二次方程式]

==>(x+2)^2-(2x-1)(x+2)=0
==>(x+2)[(x+2)-(2x-1)]=0
==>(x+2)(-x+3)=0
==>-(x+2)(x-3)=0
==>x=-2,x=3

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