數學基礎-幫我出題庫的題目N題`，要解答不要過程

(√3+√2)/(√3-√2)
=(√3+√2)^2/(√3-√2)(√3+√2)
=5+2√6=a+b√6

==>a=5,b=2

a+b=7

2012-12-17 08:56:13 補充：
x=2+√2/2*{√2+√2}(大括號是指雙重根號，根號的2加根號2，雙重根號不會打..)，X=?答案是:{2+√2}/2。

√2/(2-√ 3)=2√a+ √b ,求b-a=? 答案是:4

√6/(2√3- √6)=a+√b,求a*b=?答案是:2

已知a=(3+2√2)/(3-2√2), b=(3-2√2)/(3+2√2),求a^2b+ab^2=?答案是:34

2012-12-17 12:45:21 補充：
已知a=(3+2√2)/(3-2√2), b=(3-2√2)/(3+2√2),求a^2b+ab^2=?答案是:34
a^2b+ab^2
=ab(a+b)=1*34=34

ab=(3+2√2)/(3-2√2)(3-2√2)/(3+2√2)=(9-8)/(9-8)=1

a+b=(3+2√2)/(3-2√2)+(3-2√2)/(3+2√2)
=[(3+2√2)^2/(3-2√2)(3+2√2)]+ [(3-2√2)^2/(3+2√2)(3-2√2)]
=9+8+12√2+9+8-12√2
=34

2012-12-17 12:55:02 補充：
1/(√2+1) = ? √2-1

請參考
http://csm00.csu.edu.tw/0166/MathforCalculus_AV_freeLectures/94hsmath/313.htm

設(√3+√2)/(√3-√2)=a+b√6，則a+b=?
Sol
(√3+√2)/(√3-√2)
=(√3+√2)^2/[(√3-√2)(√3+√2)]
=(7+2√6)/1
=7+2√6
令b=0
a=7+2√6
a+b=7+2√6
解答無限多組