Would a object which is moving transfer all of its energy to another object it contact while it stops dead?

You are correct. Some of the momentum is transfered to air instead of to the second ball, creating the pressure wave we call sound.

In classroom physics problems, we tend to ignore the small loss of energy to sound, friction, etc. whenever possible. The wiki statement is trying to convey the fact that momentum is conserved: the total momentum after collision is equal to the total momentum before collision.

If the first ball does NOT stop dead but instead deflects off to the side, then you would still use conservation of momentum - now in two dimensions - to calculate the motion of the second ball. Or more applicable in pool, you can use the intended trajectory of the second ball to calculate the angle you want the ball to deflect at. This is complicated enough without including the small fraction of the energy that is lost to sound.

during collision energy will be released in the form of sound energy and heat.but in the case of pool
game energy lost during collision is negligible and can be neglected

Wiki is fairly correct.. but its only in certain cases. Not everything that collides makes a sound (differences between elastic and inelastic collisions). So, technically the sound would be counted, but only in certain cases, with this being one of them. But yes, it is a law of physics that energy is conserved.