(α^2)+(β^2)點解 = (α+β)^2 - 2αβ?
回答 (4)
2012-12-15 7:36 pm
2012-12-13 7:09 am
(α+β)^2=α^2+β^2+2αβ
(α^2)+(β^2)= (α+β)^2 - 2αβ
= α^2+β^2+2αβ - 2αβ
=α^2+β^2
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121212000051KK00350