(用first principles)
y=開方(sin(x^2)
3 find the equation of targent to the curve
y=in(x+3)^2
更新1:
3 x=0
基本微積分問題
2012-12-11 6:33 pm
f(x)=x^1/2
(用first principles)
y=開方(sin(x^2)
3 find the equation of targent to the curve
y=in(x+3)^2
(用first principles)
y=開方(sin(x^2)
3 find the equation of targent to the curve
y=in(x+3)^2
回答 (2)
2012-12-11 7:40 pm
✔ 最佳答案
For Q3, at which point?2012-12-11 11:40:52 補充：
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參考: 原創答案
2012-12-11 7:19 pm
For Q3, at which point?
x=0
x=0
收錄日期: 2021-04-23 23:32:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121211000051KK00047