1) Suppose a graph of P against V is plotted at constant 50°C, how the graph will be if the experiment is repeated at 90°C?
2) Suppose a graph of P against 1/V is plotted at constant 50°C, how the graph will be if the experiment is repeated at 90°C?
About Boyle's Law
2012-12-11 2:26 am
回答 (2)
2012-12-12 6:25 pm
✔ 最佳答案
PV=(mol) R T(1) P=(mol)RT/V
higher temp=>Same curve but higher than the original one.
(2) slope=(mol)RT, passing origin (0, 0)
higher temp=>slope is higher.
2012-12-12 10:26:50 補充：
Use mathematics to help you solve physics problems.
2012-12-11 3:59 am
1. The graph at 90'C is of similar shape to the one at 50'C, and is above the 50'C curve.
2. A plot of P against 1/V is a straight line with +ve slope passing through the origin. The graph at 90'C is of a larger slope than the one at 50'C
2. A plot of P against 1/V is a straight line with +ve slope passing through the origin. The graph at 90'C is of a larger slope than the one at 50'C
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