續多項數[help]~~~~~~急急!!!!thxx

2012-12-10 3:37 am
找餘式
1.(x^3-4x^2+8x+6)/(x+1)

2.(x^2-2x-1)/(2x+1)


thanks!!!!!!!!!

回答 (2)

2012-12-10 7:26 am
✔ 最佳答案
稍後補答````````````````````

2012-12-09 23:41:33 補充:
by remainder theorem,

1. the remainder = f(-1)=(-1)^3-4(-1)^2+8(-1)+6 = -7
2. the remainder = f(-0.5)=(-0.5)^2-2(-0.5)-1 = 0.25
2012-12-10 3:43 am
(x^3-4x^2+8x+6)/(x+1)!?


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