因式分解2x^2+2x+3xy+y+y^2

2012-12-07 6:36 am

回答 (4)

2012-12-07 6:49 am

✔ 最佳答案

2x² + 2x + 3xy + y + y²

= (2x² + 3xy + y²) + (2x + y)

= (2x + y)(x + y) + (2x + y)

= (2x + y) [(x + y) + 1]

= (2x + y)(x + y + 1)

參考: micatkie

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2012-12-08 8:52 pm

2x² + 2x + 3xy + y + y²
=(2x²+ 3xy + y²)+ 2x + y
=(2x+ y)²+( 2x + y)
=( 2x + y)+(2x+ y+1)

參考: me~

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2012-12-08 5:51 am

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2012-12-08 2:47 am

2x^2+2x+3xy+y+y^2
=(2x+y)(x+1)+(2x+y)
=(2x+y)(x+2)

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