Integration by Substitution
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2012-12-03 11:24 am
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參考: pingshek
2012-12-03 3:26 am
Let y^2=x => 2ydy=dxw=∫(x+1)dx/(√x-1) =∫(y^2+1)2ydy/(y-1) =2∫(y^3+y)dy/(y-1) =2∫[(y^2+y+2)+2/(y-1)]dy=2(y^3/3+y^2/2+2Ln|y-1|)+c=2y^3/3+y^2+4Ln|y-1|+c
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121202000015KK03673