Integration by Substitution
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2012-12-03 10:45 am
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參考: 戇戇居士
2012-12-03 3:18 am
Let y^2=x => 2ydy=dxw=∫(1-√x)dx/(1+√x)=∫(1-y)2ydy/(1+y)=-2∫(y^2-y)dy/(y+1)=-2∫[(y-2)+2/(y+1)]dy=-2[y^2/2-2y+2Ln|y+1|]+c=-(y^2-4y+4Ln|y+1|)+c
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121202000010KK03684