Integration by Substitution

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http://i841.photobucket.com/albums/zz333/tammie_0666/integration_by_substitution.png

Let y^2=x => 2ydy=dxw=∫(1-√x)dx/(1+√x)=∫(1-y)2ydy/(1+y)=-2∫(y^2-y)dy/(y+1)=-2∫[(y-2)+2/(y+1)]dy=-2[y^2/2-2y+2Ln|y+1|]+c=-(y^2-4y+4Ln|y+1|)+c