As follows:
圖片參考：http://i707.photobucket.com/albums/ww74/stevieg90/ScreenHunter_90Nov291439.jpg
超難幾何問題 求比例
2012-11-29 10:43 pm
回答 (4)
2012-11-29 11:28 pm
✔ 最佳答案
AE : EB = △AEF : △EBF ...... (1)
= △AEC : △EBC ..... (2)
= (△AEC - △AEF) : (△EBC - △EBF) ...... (2) - (1)
= △AFC : △BFC
= △AFC : (△FDC + △FBD)
= △AFC : (2△FDC) ...... ∵ BD = DC , ∴ △FDC = △FBD
= AF : 2FD
= 1 : 2(4)
= 1 : 8 Choose C.
2012-11-30 7:44 pm
用 Ceva 不就行了嗎
2012-11-30 1:07 am
哈哈 寫到標題咁樣先吸引到D人答!
2012-11-30 12:47 am
Maybe you haven't seen some true difficult geometry questions...
2012-11-29 17:38:53 補充：
But this disappointed me after reading the question... lol
2012-11-30 17:21:04 補充：
Alternative solution: using Menelaus' theorem.
BC/DC*DF/FA*AE/EB = 1
AE/EB = FA/DF*DC/BC
= 1/4*1/2 = 1/8
2012-11-29 17:38:53 補充：
But this disappointed me after reading the question... lol
2012-11-30 17:21:04 補充：
Alternative solution: using Menelaus' theorem.
BC/DC*DF/FA*AE/EB = 1
AE/EB = FA/DF*DC/BC
= 1/4*1/2 = 1/8
收錄日期: 2021-04-11 19:22:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121129000051KK00156