唔識做以下題目，希望可以得到解答，（有解釋就最好) 感謝萬分: )
in an experiment,two heated oxides X and Y of the same metal M were completely
reduced by hydrogen. The result were recorded as follows:
1) mass of oxide X=42.9g , mass of metal M left = 38.1 g
2) mass of oxide Y= 15.9 g ,mass of metal M left =12.7g
if the formula of oxide X is M2O, what is the formula of oxide Y?
(relative atomic mass : O=16.0)
THX !
chemistry empirical formula
2012-11-21 4:44 am
回答 (1)
2012-11-21 8:51 pm
✔ 最佳答案
Let m g/mol be the molar mass of M.In X, molar ratio M : O = 2 : 1
38.1/m : (42.9 - 32.1)/16 = 2 : 1
38.1/m : 0.3 = 2 : 1
38.1/m = 0.6
m = 63.5
In Y, mole ratio M : O
= 12.7/63.5 : (15.9 - 12.7)/16
= 0.2 : 0.2
= 1 : 1
Empirical formula of Y = MO
參考: 不用客氣
收錄日期: 2021-04-13 19:08:09
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121120000051KK00376