A horizontal wire is stretched with a tension of 85.0 N , and the speed of transverse waves for the wire is 492 ms^-1 .
What must the amplitude of a traveling wave of frequency 61.0 hz be in order for the average power carried by the wave to be 0.365 W ?
Express your answer with the appropriate units.
A=?
physics problem
2012-11-19 12:46 pm
回答 (1)
2012-11-19 6:35 pm
✔ 最佳答案
Speed of wave v in a stretched string is given by,v^2 = T/p
where T is the string tension and p is the linear density of the string
hence, 492^2 = 85/p
p = 3.511 x 10^-4 kg/m
The power P carried by the travelling wave along a stretched string is,
P = (1/2)pv(wA)^2
where w is the angular frequency of the wave, and A is the wave amplitude
Hence, 0.365 = (1/2).(3.511x10^-4).(492).[(2.pi.61).A]^2
A = 5.36 x 10^-3 m
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