A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499 cm^(3) of air at atmospheric pressure (1.01*10^(5) Pa) and a temperature of 27.0 oC. At the end of the stroke, the air has been compressed to a volume of 46.2 cm^(3) and the gauge pressure has increased to 2.72*10^(6) Pa. Compute the final temperature.
The correct answer is 503 oC. I want to know the approach. Thx.
Physics Help!!! 20 Points
2012-11-19 1:22 am
回答 (3)
2012-11-19 2:49 am
✔ 最佳答案
Use the ideal gas equation: (P1).(V1)/T1 = (P2).(V2)/T2where the P, V and T denote the pressure, volume and absolute temperature of a given mass of gas respectively.
Mow, given:
P1 = 1.01 x 10^5 Pa
V1 = 499 cm^2
T1 = (273+27) K = 300 K
P2 = (2.72x10^6 + 1.01x10^5) Pa = 2.82 x 10^6 Pa
V2 = 46.2 cm^3
Hence, [(1.05x10^5) x 499]/300 = [(2.82x10^6) x 46.2]/T2
T2 = 776 K = (776 - 273)'C = 503'C
2013-10-17 11:40 pm
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2012-11-20 6:34 pm
Assume the working substance is ideal gas.
Equation of state for ideal gas:
P V = (mol) R T
P1 V1/T1 = P2 V2/T2
Equation of state for ideal gas:
P V = (mol) R T
P1 V1/T1 = P2 V2/T2
收錄日期: 2021-04-29 17:47:53
原文連結 [永久失效]:
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