CHEM 's QUESTION

2012-11-18 11:27 pm
Isotope (MASS 35)Cl (MASS 37)Cl
Relative abundance(%) 75 25

Q1
Calculate
i)the ratio of all different existing chlorine molecules?



I DON'T NEED ANYONE TO TRANSLATION THE QUESTION FOR ME!!!!!!

回答 (1)

2012-11-19 8:13 am
✔ 最佳答案
Cl2 molecule with relative molecular mass 70 contains two Cl-35atoms.
Relative abundance = 75% x 75% = 9/16

Cl2 molecule with relative molecular mass 72 contains one Cl-35 atomand one Cl-37 atom.
Relative abundance = 75% x 25% + 25% x 75% = 3/8

Cl2 molecule with relative molecular mass 74 contains two Cl-37atoms.
Relative abundance = 25% x 25% = 1/16

(Cl2­ with relative molecular mass 70) : (Cl2­ withrelative molecular mass 72) : (Cl2­ with relative molecular mass 74)
= (9/16) : (3/8) : (1/16)
= (9/16) : (6/16) : (1/16)
= 9 : 6 : 1
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