In an experiment,a sample of 24.08 g iron burns in oxygen to form an oxide.
What is the formula of the oxide if the oxide contains 70% of iron by mass?
How to solve
also can anyone please find out where does this question come from
textbook,exercise and give me the name
Thanks
About a chemistry qustion
2012-11-17 6:09 pm
回答 (3)
2012-11-18 12:39 am
✔ 最佳答案
Mass of Fe in the oxide = 24.08 gTotal mass of the oxide = 24.08/70% = 34.40 g
Mass of O in the oxide = 34.40 - 24.08 = 10.32 g
Mole ratio Fe : O = 24.08/56 : 10.32/16 = 0.43 : 0.645 = 2 : 3
Empirical formula = Fe2O3
參考: 賣女孩的火柴
2012-11-18 4:08 am
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2012-11-18 1:35 am
I need to know where did this question come from,please it is important
2012-11-17 20:17:13 補充：
Thanks a lot
2012-11-17 20:17:13 補充：
Thanks a lot
收錄日期: 2021-04-13 19:07:30
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121117000051KK00078