因式分解題目
回答 (2)
2012-11-18 3:46 am
✔ 最佳答案
14^8-32×14^4+256=14^8-32×14^4+16^2
=(14^4)^2-2*16*(14^4)+16^2
=(14^4-16)^2
=38400^2
=(2^9*3*5^2)^2
=2^18*3^2*5^4
2012-11-17 19:48:44 補充：
利用a^2-2ab+b^2=(a-b)^2
2012-11-18 4:35 am
14^8 - 32x14^4 + 256
= (14^4 - 16)^2
= [(14^2 + 4)(14 + 2)(14 - 2)]^2
= (200 x 16 x 12)^2
= (2^3 x 5^2 x 2^4 x 2^2 x 3)^2
= 2^18 x 3^2 x 5^4
= (14^4 - 16)^2
= [(14^2 + 4)(14 + 2)(14 - 2)]^2
= (200 x 16 x 12)^2
= (2^3 x 5^2 x 2^4 x 2^2 x 3)^2
= 2^18 x 3^2 x 5^4
收錄日期: 2021-04-13 19:06:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121117000016KK04295