sigma(t=12 ,一直加到17) (8t^2-5t+3)=?
(如果吾明上面，我可以SEND張用小畫家寫的式比你)
數學 summation (詳細步驟+答案)
2012-11-03 7:28 pm
回答 (2)
2012-11-04 10:01 am
✔ 最佳答案
summation(t=12 to 17) (8t^2-5t+3)= sum(12-17) 8t^2 - sum(12-17) 5t + sum(12-17) 3
= 8( 12^2 +13^2 +14^2 +15^2 +16^2 + 17^2) - 5(12+13+14+15+16+17) + 3(6)
= 8(1279) -5(87) +18
= 10232 - 435 + 18
= 9815
參考: maeducation.edu.hk
2012-11-04 3:17 am
收錄日期: 2021-04-17 02:18:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121103000051KK00139