1.Factorize (x-3)(1+2y)-(2+y)(x-3)
2.Use the result of (1) ,factorize
2xsquare-3(x+3)+(x-3)(1+2y)-(2+y)(x-3)
**2xsquare-3(x+3) is identical to (2x+3)(x-3)
Maths Qs 6
2012-11-03 7:04 pm
回答 (2)
2012-11-03 7:09 pm
✔ 最佳答案
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2012-11-03 11:10:43 補充：
文字版：
(1)
(x-3)(1+2y)-(2+y)(x-3)
=(x-3)[(1+2y)-(2+y) ]
=(x-3)(1+2y-2-y)
=(x-3)(y-1)
(2)
2x^2-3(x+3)+(x-3)(1+2y)-(2+y)(x-3)
=[2x^2-3(x+3) ]+[(x-3)(1+2y)-(2+y)(x-3)]
=(2x+3)(x-3)+(x-3)(y-1)
=(x-3)[(2x+3)+(y-1)]
=(x-3)(2x+3+y-1)
=(x-3)(2x+y+2)
2012-11-11 10:10 pm
1)(x-3)(1+2y)-(2+y)(x-3)
=(x-3)[(1+2y)-(2+y) ]
=(x-3)(1+2y-2-y)
=(x-3)(y-1)
2)2x^2-3(x+3)+(x-3)(1+2y)-(2+y)(x-3)
=[2x^2-3(x+3) ]+[(x-3)(1+2y)-(2+y)(x-3)]
=(2x+3)(x-3)+(x-3)(y-1)
=(x-3)[(2x+3)+(y-1)]
=(x-3)(2x+3+y-1)
=(x-3)(2x+y+2)
=(x-3)[(1+2y)-(2+y) ]
=(x-3)(1+2y-2-y)
=(x-3)(y-1)
2)2x^2-3(x+3)+(x-3)(1+2y)-(2+y)(x-3)
=[2x^2-3(x+3) ]+[(x-3)(1+2y)-(2+y)(x-3)]
=(2x+3)(x-3)+(x-3)(y-1)
=(x-3)[(2x+3)+(y-1)]
=(x-3)(2x+3+y-1)
=(x-3)(2x+y+2)
收錄日期: 2021-04-20 13:51:43
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20121103000051KK00122