急 ! F5 數1條,問 ! 的計法

2012-10-28 9:45 pm
請詳解釋下條計法的原因 :
(不要綱址回答)

If (n+1)!+(n+1) x 3! = (n+2)! , find n
(n+1)!+(n+1)x3!=(n+2)(n+1)!
(n+1)!+(n+1)x3!=(n+2)(n+1)!
(n+1)x3!=(n+1)(n+1)! [點解右邊冇咗(n+1)!,而右邊(n+2)變咗(n+1)
3!=(n+1)!
n=2

回答 (1)

2012-10-28 11:16 pm
✔ 最佳答案
If (n+1)!+(n+1) x 3! = (n+2)! , find n
(n+1)!+(n+1)x3!=(n+2)(n+1)!
(n+1)x3!=(n+2)(n+1)! - (n+1)!
(n+1)x3!=(n+2-1)(n+1)!
(n+1)x3!=(n+1)(n+1)!
3!=(n+1)!
3=n+1
n=2


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